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TODO 1851. Minimum Interval to Include Each Query   hard

You are given a 2D integer array intervals, where intervals[i] = [left_{i}, right_{i}] describes the i^{th} interval starting at left_{i} and ending at right_{i} (inclusive). The size of an interval is defined as the number of integers it contains, or more formally right_{i} - left_{i} + 1.

You are also given an integer array queries. The answer to the j^{th} query is the size of the smallest interval i such that left_{i} <= queries[j] <= right_{i}. If no such interval exists, the answer is -1.

Return an array containing the answers to the queries.

Example 1:

Input: intervals = [[1,4],[2,4],[3,6],[4,4]], queries = [2,3,4,5]
Output: [3,3,1,4]
Explanation: The queries are processed as follows:
- Query = 2: The interval [2,4] is the smallest interval containing 2. The answer is 4 - 2 + 1 = 3.
- Query = 3: The interval [2,4] is the smallest interval containing 3. The answer is 4 - 2 + 1 = 3.
- Query = 4: The interval [4,4] is the smallest interval containing 4. The answer is 4 - 4 + 1 = 1.
- Query = 5: The interval [3,6] is the smallest interval containing 5. The answer is 6 - 3 + 1 = 4.

Example 2:

Input: intervals = [[2,3],[2,5],[1,8],[20,25]], queries = [2,19,5,22]
Output: [2,-1,4,6]
Explanation: The queries are processed as follows:
- Query = 2: The interval [2,3] is the smallest interval containing 2. The answer is 3 - 2 + 1 = 2.
- Query = 19: None of the intervals contain 19. The answer is -1.
- Query = 5: The interval [2,5] is the smallest interval containing 5. The answer is 5 - 2 + 1 = 4.
- Query = 22: The interval [20,25] is the smallest interval containing 22. The answer is 25 - 20 + 1 = 6.

Constraints:

  • 1 <= intervals.length <= 10^{5}
  • 1 <= queries.length <= 10^{5}
  • intervals[i].length == 2
  • 1 <= left_{i} <= right_{i} <= 10^{7}
  • 1 <= queries[j] <= 10^{7}

TODO Approach

Write your approach here.

TODO Python

class Solution:
    def minInterval(self, intervals: List[List[int]], queries: List[int]) -> List[int]:

TODO C++

class Solution {
public:
    vector<int> minInterval(vector<vector<int>>& intervals, vector<int>& queries) {
        
    }
};