1.3 KiB
1.3 KiB
TODO 0056. Merge Intervals medium
Given an array of intervals where intervals[i] = [start_{i}, end_{i}], merge all overlapping intervals, and return an array of the non-overlapping intervals that cover all the intervals in the input.
Example 1:
Input: intervals = [[1,3],[2,6],[8,10],[15,18]]
Output: [[1,6],[8,10],[15,18]]
Explanation: Since intervals [1,3] and [2,6] overlap, merge them into [1,6].
Example 2:
Input: intervals = [[1,4],[4,5]]
Output: [[1,5]]
Explanation: Intervals [1,4] and [4,5] are considered overlapping.
Example 3:
Input: intervals = [[4,7],[1,4]]
Output: [[1,7]]
Explanation: Intervals [1,4] and [4,7] are considered overlapping.
Constraints:
1 <= intervals.length <= 10^{4}intervals[i].length == 20 <= start_{i} <= end_{i} <= 10^{4}
TODO Approach
Write your approach here.
TODO Python
class Solution:
def merge(self, intervals: List[List[int]]) -> List[List[int]]:
TODO C++
class Solution {
public:
vector<vector<int>> merge(vector<vector<int>>& intervals) {
}
};