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TODO 0056. Merge Intervals   medium

Given an array of intervals where intervals[i] = [start_{i}, end_{i}], merge all overlapping intervals, and return an array of the non-overlapping intervals that cover all the intervals in the input.

Example 1:

Input: intervals = [[1,3],[2,6],[8,10],[15,18]]
Output: [[1,6],[8,10],[15,18]]
Explanation: Since intervals [1,3] and [2,6] overlap, merge them into [1,6].

Example 2:

Input: intervals = [[1,4],[4,5]]
Output: [[1,5]]
Explanation: Intervals [1,4] and [4,5] are considered overlapping.

Example 3:

Input: intervals = [[4,7],[1,4]]
Output: [[1,7]]
Explanation: Intervals [1,4] and [4,7] are considered overlapping.

Constraints:

  • 1 <= intervals.length <= 10^{4}
  • intervals[i].length == 2
  • 0 <= start_{i} <= end_{i} <= 10^{4}

TODO Approach

Write your approach here.

TODO Python

class Solution:
    def merge(self, intervals: List[List[int]]) -> List[List[int]]:

TODO C++

class Solution {
public:
    vector<vector<int>> merge(vector<vector<int>>& intervals) {
        
    }
};