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TODO 0719. Find K-th Smallest Pair Distance   hard

The distance of a pair of integers a and b is defined as the absolute difference between a and b.

Given an integer array nums and an integer k, return the k^{th} smallest distance among all the pairs nums[i] and nums[j] where 0 <= i < j < nums.length.

Example 1:

Input: nums = [1,3,1], k = 1
Output: 0
Explanation: Here are all the pairs:
(1,3) -> 2
(1,1) -> 0
(3,1) -> 2
Then the 1st smallest distance pair is (1,1), and its distance is 0.

Example 2:

Input: nums = [1,1,1], k = 2
Output: 0

Example 3:

Input: nums = [1,6,1], k = 3
Output: 5

Constraints:

  • n == nums.length
  • 2 <= n <= 10^{4}
  • 0 <= nums[i] <= 10^{6}
  • 1 <= k <= n * (n - 1) / 2

TODO Approach

Write your approach here.

TODO Python

class Solution:
    def smallestDistancePair(self, nums: List[int], k: int) -> int:

TODO C++

class Solution {
public:
    int smallestDistancePair(vector<int>& nums, int k) {
        
    }
};