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TODO 0719. Find K-th Smallest Pair Distance hard
The distance of a pair of integers a and b is defined as the absolute difference between a and b.
Given an integer array nums and an integer k, return the k^{th} smallest distance among all the pairs nums[i] and nums[j] where 0 <= i < j < nums.length.
Example 1:
Input: nums = [1,3,1], k = 1
Output: 0
Explanation: Here are all the pairs:
(1,3) -> 2
(1,1) -> 0
(3,1) -> 2
Then the 1st smallest distance pair is (1,1), and its distance is 0.
Example 2:
Input: nums = [1,1,1], k = 2
Output: 0
Example 3:
Input: nums = [1,6,1], k = 3
Output: 5
Constraints:
n == nums.length2 <= n <= 10^{4}0 <= nums[i] <= 10^{6}1 <= k <= n * (n - 1) / 2
TODO Approach
Write your approach here.
TODO Python
class Solution:
def smallestDistancePair(self, nums: List[int], k: int) -> int:
TODO C++
class Solution {
public:
int smallestDistancePair(vector<int>& nums, int k) {
}
};