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TODO 0704. Binary Search   easy

Given an array of integers nums which is sorted in ascending order, and an integer target, write a function to search target in nums. If target exists, then return its index. Otherwise, return -1.

You must write an algorithm with O(log n) runtime complexity.

Example 1:

Input: nums = [-1,0,3,5,9,12], target = 9
Output: 4
Explanation: 9 exists in nums and its index is 4

Example 2:

Input: nums = [-1,0,3,5,9,12], target = 2
Output: -1
Explanation: 2 does not exist in nums so return -1

Constraints:

  • 1 <= nums.length <= 10^{4}
  • -10^{4} < nums[i], target < 10^{4}
  • All the integers in nums are unique.
  • nums is sorted in ascending order.

TODO Approach

Write your approach here.

TODO Python

class Solution:
    def search(self, nums: List[int], target: int) -> int:

TODO C++

class Solution {
public:
    int search(vector<int>& nums, int target) {
        
    }
};