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• 2658. Maximum Number of Fish in a Grid
  • Approach
  • Python
  • C++

TODO 2658. Maximum Number of Fish in a Grid   medium

You are given a 0-indexed 2D matrix grid of size m x n, where (r, c) represents:

• A land cell if grid[r][c] = 0, or
• A water cell containing grid[r][c] fish, if grid[r][c] > 0.

A fisher can start at any water cell (r, c) and can do the following operations any number of times:

• Catch all the fish at cell (r, c), or
• Move to any adjacent water cell.

Return /the maximum number of fish the fisher can catch if he chooses his starting cell optimally, or /~0~ if no water cell exists.

An adjacent cell of the cell (r, c), is one of the cells (r, c + 1), (r, c - 1), (r + 1, c) or (r - 1, c) if it exists.

Example 1:

Input: grid = [[0,2,1,0],[4,0,0,3],[1,0,0,4],[0,3,2,0]]
Output: 7
Explanation: The fisher can start at cell (1,3) and collect 3 fish, then move to cell (2,3) and collect 4 fish.

Example 2:

Input: grid = [[1,0,0,0],[0,0,0,0],[0,0,0,0],[0,0,0,1]]
Output: 1
Explanation: The fisher can start at cells (0,0) or (3,3) and collect a single fish.

Constraints:

• m == grid.length
• n == grid[i].length
• 1 <= m, n <= 10
• 0 <= grid[i][j] <= 10

TODO Approach

Write your approach here.

TODO Python

class Solution:
    def findMaxFish(self, grid: List[List[int]]) -> int:

TODO C++

class Solution {
public:
    int findMaxFish(vector<vector<int>>& grid) {
        
    }
};