1.2 KiB
1.2 KiB
TODO 0704. Binary Search easy
Given an array of integers nums which is sorted in ascending order, and an integer target, write a function to search target in nums. If target exists, then return its index. Otherwise, return -1.
You must write an algorithm with O(log n) runtime complexity.
Example 1:
Input: nums = [-1,0,3,5,9,12], target = 9
Output: 4
Explanation: 9 exists in nums and its index is 4Example 2:
Input: nums = [-1,0,3,5,9,12], target = 2
Output: -1
Explanation: 2 does not exist in nums so return -1Constraints:
1 <= nums.length <= 10^{4}-10^{4} < nums[i], target < 10^{4}- All the integers in
numsare unique. numsis sorted in ascending order.
TODO Approach
Write your approach here.
TODO Python
class Solution:
def search(self, nums: List[int], target: int) -> int:TODO C++
class Solution {
public:
int search(vector<int>& nums, int target) {
}
};