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TODO 0329. Longest Increasing Path In a Matrix   hard

Given an m x n integers matrix, return /the length of the longest increasing path in /~matrix~.

From each cell, you can either move in four directions: left, right, up, or down. You may not move diagonally or move outside the boundary (i.e., wrap-around is not allowed).

Example 1:

Input: matrix = [[9,9,4],[6,6,8],[2,1,1]]
Output: 4
Explanation: The longest increasing path is [1, 2, 6, 9].

Example 2:

Input: matrix = [[3,4,5],[3,2,6],[2,2,1]]
Output: 4
Explanation: The longest increasing path is [3, 4, 5, 6]. Moving diagonally is not allowed.

Example 3:

Input: matrix = [[1]]
Output: 1

Constraints:

  • m == matrix.length
  • n == matrix[i].length
  • 1 <= m, n <= 200
  • 0 <= matrix[i][j] <= 2^{31} - 1

TODO Approach

Write your approach here.

TODO Python

class Solution:
    def longestIncreasingPath(self, matrix: List[List[int]]) -> int:

TODO C++

class Solution {
public:
    int longestIncreasingPath(vector<vector<int>>& matrix) {
        
    }
};