1.3 KiB
1.3 KiB
TODO 0329. Longest Increasing Path In a Matrix hard
Given an m x n integers matrix, return /the length of the longest increasing path in /~matrix~.
From each cell, you can either move in four directions: left, right, up, or down. You may not move diagonally or move outside the boundary (i.e., wrap-around is not allowed).
Example 1:
Input: matrix = [[9,9,4],[6,6,8],[2,1,1]]
Output: 4
Explanation: The longest increasing path is [1, 2, 6, 9].
Example 2:
Input: matrix = [[3,4,5],[3,2,6],[2,2,1]]
Output: 4
Explanation: The longest increasing path is [3, 4, 5, 6]. Moving diagonally is not allowed.
Example 3:
Input: matrix = [[1]]
Output: 1
Constraints:
m == matrix.lengthn == matrix[i].length1 <= m, n <= 2000 <= matrix[i][j] <= 2^{31} - 1
TODO Approach
Write your approach here.
TODO Python
class Solution:
def longestIncreasingPath(self, matrix: List[List[int]]) -> int:
TODO C++
class Solution {
public:
int longestIncreasingPath(vector<vector<int>>& matrix) {
}
};