#+PROPERTY: STUDY_DECK_02
* TODO 0347. Top K Frequent Elements :medium:
:PROPERTIES:
:NEETCODE: [[file:../../roadmap.org::*0347. Top K Frequent Elements][0347. Top K Frequent Elements]]
:END:

Given an integer array ~nums~ and an integer ~k~, return /the/ ~k~ /most frequent elements/. You may return the answer in *any order*.

*Example 1:*

*Input:* nums = [1,1,1,2,2,3], k = 2

*Output:* [1,2]

*Example 2:*

*Input:* nums = [1], k = 1

*Output:* [1]

*Example 3:*

*Input:* nums = [1,2,1,2,1,2,3,1,3,2], k = 2

*Output:* [1,2]

*Constraints:*

 - ~1 <= nums.length <= 10^{5}~

 - ~-10^{4} <= nums[i] <= 10^{4}~

 - ~k~ is in the range ~[1, the number of unique elements in the array]~.

 - It is *guaranteed* that the answer is *unique*.

*Follow up:* Your algorithm's time complexity must be better than ~O(n log n)~, where n is the array's size.

** TODO Approach
Write your approach here.

** TODO Python
#+begin_src python
class Solution:
    def topKFrequent(self, nums: List[int], k: int) -> List[int]:
#+end_src

** TODO C++
#+begin_src cpp
class Solution {
public:
    vector<int> topKFrequent(vector<int>& nums, int k) {
        
    }
};
#+end_src