#+PROPERTY: STUDY_DECK_02
* TODO 0066. Plus One :easy:
:PROPERTIES:
:NEETCODE: [[file:../../roadmap.org::*0066. Plus One][0066. Plus One]]
:END:

You are given a *large integer* represented as an integer array ~digits~, where each ~digits[i]~ is the ~i^{th}~ digit of the integer. The digits are ordered from most significant to least significant in left-to-right order. The large integer does not contain any leading ~0~'s.

Increment the large integer by one and return /the resulting array of digits/.

*Example 1:*


#+begin_src
Input: digits = [1,2,3]
Output: [1,2,4]
Explanation: The array represents the integer 123.
Incrementing by one gives 123 + 1 = 124.
Thus, the result should be [1,2,4].
#+end_src


*Example 2:*


#+begin_src
Input: digits = [4,3,2,1]
Output: [4,3,2,2]
Explanation: The array represents the integer 4321.
Incrementing by one gives 4321 + 1 = 4322.
Thus, the result should be [4,3,2,2].
#+end_src


*Example 3:*


#+begin_src
Input: digits = [9]
Output: [1,0]
Explanation: The array represents the integer 9.
Incrementing by one gives 9 + 1 = 10.
Thus, the result should be [1,0].
#+end_src


*Constraints:*

 - ~1 <= digits.length <= 100~

 - ~0 <= digits[i] <= 9~

 - ~digits~ does not contain any leading ~0~'s.

** TODO Approach
Write your approach here.

** TODO Python
#+begin_src python
class Solution:
    def plusOne(self, digits: List[int]) -> List[int]:
#+end_src

** TODO C++
#+begin_src cpp
class Solution {
public:
    vector<int> plusOne(vector<int>& digits) {
        
    }
};
#+end_src