#+ANKI_DECK: study_deck_02
* TODO 0054. Spiral Matrix :medium:
:PROPERTIES:
:NEETCODE: [[file:../../roadmap.org::*0054. Spiral Matrix][0054. Spiral Matrix]]
:END:

Given an ~m x n~ ~matrix~, return /all elements of the/ ~matrix~ /in spiral order/.

*Example 1:*


#+begin_src
Input: matrix = [[1,2,3],[4,5,6],[7,8,9]]
Output: [1,2,3,6,9,8,7,4,5]
#+end_src


*Example 2:*


#+begin_src
Input: matrix = [[1,2,3,4],[5,6,7,8],[9,10,11,12]]
Output: [1,2,3,4,8,12,11,10,9,5,6,7]
#+end_src


*Constraints:*

 - ~m == matrix.length~

 - ~n == matrix[i].length~

 - ~1 <= m, n <= 10~

 - ~-100 <= matrix[i][j] <= 100~

** TODO Approach
Write your approach here.

** TODO Python
#+begin_src python
class Solution:
    def spiralOrder(self, matrix: List[List[int]]) -> List[int]:
#+end_src

** TODO C++
#+begin_src cpp
class Solution {
public:
    vector<int> spiralOrder(vector<vector<int>>& matrix) {
        
    }
};
#+end_src