#+ANKI_DECK: study_deck_02
* TODO 2812. Find the Safest Path in a Grid :medium:
:PROPERTIES:
:NEETCODE: [[file:../../roadmap.org::*2812. Find the Safest Path in a Grid][2812. Find the Safest Path in a Grid]]
:END:

You are given a *0-indexed* 2D matrix ~grid~ of size ~n x n~, where ~(r, c)~ represents:

 - A cell containing a thief if ~grid[r][c] = 1~

 - An empty cell if ~grid[r][c] = 0~

You are initially positioned at cell ~(0, 0)~. In one move, you can move to any adjacent cell in the grid, including cells containing thieves.

The *safeness factor* of a path on the grid is defined as the *minimum* manhattan distance from any cell in the path to any thief in the grid.

Return /the *maximum safeness factor* of all paths leading to cell /~(n - 1, n - 1)~/./

An *adjacent* cell of cell ~(r, c)~, is one of the cells ~(r, c + 1)~, ~(r, c - 1)~, ~(r + 1, c)~ and ~(r - 1, c)~ if it exists.

The *Manhattan distance* between two cells ~(a, b)~ and ~(x, y)~ is equal to ~|a - x| + |b - y|~, where ~|val|~ denotes the absolute value of val.

*Example 1:*


#+begin_src
Input: grid = [[1,0,0],[0,0,0],[0,0,1]]
Output: 0
Explanation: All paths from (0, 0) to (n - 1, n - 1) go through the thieves in cells (0, 0) and (n - 1, n - 1).
#+end_src


*Example 2:*


#+begin_src
Input: grid = [[0,0,1],[0,0,0],[0,0,0]]
Output: 2
Explanation: The path depicted in the picture above has a safeness factor of 2 since:
- The closest cell of the path to the thief at cell (0, 2) is cell (0, 0). The distance between them is | 0 - 0 | + | 0 - 2 | = 2.
It can be shown that there are no other paths with a higher safeness factor.
#+end_src


*Example 3:*


#+begin_src
Input: grid = [[0,0,0,1],[0,0,0,0],[0,0,0,0],[1,0,0,0]]
Output: 2
Explanation: The path depicted in the picture above has a safeness factor of 2 since:
- The closest cell of the path to the thief at cell (0, 3) is cell (1, 2). The distance between them is | 0 - 1 | + | 3 - 2 | = 2.
- The closest cell of the path to the thief at cell (3, 0) is cell (3, 2). The distance between them is | 3 - 3 | + | 0 - 2 | = 2.
It can be shown that there are no other paths with a higher safeness factor.
#+end_src


*Constraints:*

 - ~1 <= grid.length == n <= 400~

 - ~grid[i].length == n~

 - ~grid[i][j]~ is either ~0~ or ~1~.

 - There is at least one thief in the ~grid~.

** TODO Approach
Write your approach here.

** TODO Python
#+begin_src python
class Solution:
    def maximumSafenessFactor(self, grid: List[List[int]]) -> int:
#+end_src

** TODO C++
#+begin_src cpp
class Solution {
public:
    int maximumSafenessFactor(vector<vector<int>>& grid) {
        
    }
};
#+end_src