feat: populate note files with problem descriptions and code stubs
Add populate-notes.mjs that fetches problem descriptions and Python/C++ code stubs from LeetCode's GraphQL API. Populated all 197 NeetCode 150 note files with: - Problem description (examples, constraints) - Python code stub (function signature) - C++ code stub (function signature + includes) API responses cached in leetcode/.cache/leetcode/ for instant re-runs.
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@@ -1,18 +1,73 @@
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#+PROPERTY: STUDY_DECK_02
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* TODO 0572. Subtree of Another Tree :easy:
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:PROPERTIES:
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:NEETCODE: [[file:../../roadmap.org::*0572. Subtree of Another Tree][Roadmap]]
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:NEETCODE: [[file:../../roadmap.org::*0572. Subtree of Another Tree][0572. Subtree of Another Tree]]
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:END:
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Given the roots of two binary trees ~root~ and ~subRoot~, return ~true~ if there is a subtree of ~root~ with the same structure and node values of~ subRoot~ and ~false~ otherwise.
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A subtree of a binary tree ~tree~ is a tree that consists of a node in ~tree~ and all of this node's descendants. The tree ~tree~ could also be considered as a subtree of itself.
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*Example 1:*
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#+begin_src
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Input: root = [3,4,5,1,2], subRoot = [4,1,2]
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Output: true
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#+end_src
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*Example 2:*
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#+begin_src
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Input: root = [3,4,5,1,2,null,null,null,null,0], subRoot = [4,1,2]
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Output: false
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#+end_src
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*Constraints:*
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- The number of nodes in the ~root~ tree is in the range ~[1, 2000]~.
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- The number of nodes in the ~subRoot~ tree is in the range ~[1, 1000]~.
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- ~-10^{4} <= root.val <= 10^{4}~
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- ~-10^{4} <= subRoot.val <= 10^{4}~
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** TODO Approach
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Write your approach here.
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** TODO Python
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#+begin_src python
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# Definition for a binary tree node.
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# class TreeNode:
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# def __init__(self, val=0, left=None, right=None):
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# self.val = val
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# self.left = left
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# self.right = right
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class Solution:
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def isSubtree(self, root: Optional[TreeNode], subRoot: Optional[TreeNode]) -> bool:
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#+end_src
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** TODO C++
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#+begin_src cpp
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/**
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* Definition for a binary tree node.
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* struct TreeNode {
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* int val;
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* TreeNode *left;
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* TreeNode *right;
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* TreeNode() : val(0), left(nullptr), right(nullptr) {}
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* TreeNode(int x) : val(x), left(nullptr), right(nullptr) {}
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* TreeNode(int x, TreeNode *left, TreeNode *right) : val(x), left(left), right(right) {}
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* };
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*/
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class Solution {
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public:
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bool isSubtree(TreeNode* root, TreeNode* subRoot) {
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}
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};
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#+end_src
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