2026-06-01 16:12:21 +08:00
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#+PROPERTY: STUDY_DECK_02
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2026-06-01 17:12:10 +08:00
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* TODO 0190. Reverse Bits :easy:
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2026-06-01 02:33:30 +08:00
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:PROPERTIES:
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2026-06-01 17:22:07 +08:00
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:NEETCODE: [[file:../../roadmap.org::*0190. Reverse Bits][0190. Reverse Bits]]
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2026-06-01 02:33:30 +08:00
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:END:
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2026-06-01 17:22:07 +08:00
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Reverse bits of a given 32 bits signed integer.
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*Example 1:*
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*Input:* n = 43261596
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*Output:* 964176192
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*Explanation:*
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Integer
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Binary
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43261596
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00000010100101000001111010011100
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964176192
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00111001011110000010100101000000
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*Example 2:*
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*Input:* n = 2147483644
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*Output:* 1073741822
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*Explanation:*
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Integer
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Binary
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2147483644
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01111111111111111111111111111100
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1073741822
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00111111111111111111111111111110
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*Constraints:*
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- ~0 <= n <= 2^{31} - 2~
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- ~n~ is even.
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*Follow up:* If this function is called many times, how would you optimize it?
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2026-06-01 02:39:53 +08:00
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** TODO Approach
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Write your approach here.
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** TODO Python
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#+begin_src python
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2026-06-01 17:22:07 +08:00
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class Solution:
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def reverseBits(self, n: int) -> int:
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2026-06-01 02:39:53 +08:00
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#+end_src
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** TODO C++
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2026-06-01 02:33:30 +08:00
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#+begin_src cpp
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2026-06-01 17:22:07 +08:00
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class Solution {
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public:
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int reverseBits(int n) {
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}
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};
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2026-06-01 02:33:30 +08:00
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#+end_src
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