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2026-06-01 18:12:40 +08:00
#+ANKI_DECK: study_deck_02
* TODO 0312. Burst Balloons :hard:
:PROPERTIES:
:NEETCODE: [[file:../../roadmap.org::*0312. Burst Balloons][0312. Burst Balloons]]
:END:
You are given ~n~ balloons, indexed from ~0~ to ~n - 1~. Each balloon is painted with a number on it represented by an array ~nums~. You are asked to burst all the balloons.
If you burst the ~i^{th}~ balloon, you will get ~nums[i - 1] * nums[i] * nums[i + 1]~ coins. If ~i - 1~ or ~i + 1~ goes out of bounds of the array, then treat it as if there is a balloon with a ~1~ painted on it.
Return /the maximum coins you can collect by bursting the balloons wisely/.
*Example 1:*
#+begin_src
Input: nums = [3,1,5,8]
Output: 167
Explanation:
nums = [3,1,5,8] --> [3,5,8] --> [3,8] --> [8] --> []
coins = 3*1*5 + 3*5*8 + 1*3*8 + 1*8*1 = 167
#+end_src
*Example 2:*
#+begin_src
Input: nums = [1,5]
Output: 10
#+end_src
*Constraints:*
- ~n == nums.length~
- ~1 <= n <= 300~
- ~0 <= nums[i] <= 100~
** TODO Approach
Write your approach here.
** TODO Python
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#+begin_src python :lc-problem 312 :lc-lang python3
class Solution:
def maxCoins(self, nums: List[int]) -> int:
#+end_src
** TODO C++
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#+begin_src cpp :lc-problem 312
class Solution {
public:
int maxCoins(vector<int>& nums) {
}
};
#+end_src