cpp-flashcards/org/study_deck_02/dsa/math-geometry/0009-palindrome-number.org

#+PROPERTY: STUDY_DECK_02
* TODO 0009. Palindrome Number :easy:
:PROPERTIES:
:NEETCODE: [[file:../../roadmap.org::*0009. Palindrome Number][0009. Palindrome Number]]
:END:

Given an integer ~x~, return ~true~/ if /~x~/ is a //*palindrome*//, and /~false~/ otherwise/.

*Example 1:*


#+begin_src
Input: x = 121
Output: true
Explanation: 121 reads as 121 from left to right and from right to left.
#+end_src


*Example 2:*


#+begin_src
Input: x = -121
Output: false
Explanation: From left to right, it reads -121. From right to left, it becomes 121-. Therefore it is not a palindrome.
#+end_src


*Example 3:*


#+begin_src
Input: x = 10
Output: false
Explanation: Reads 01 from right to left. Therefore it is not a palindrome.
#+end_src


*Constraints:*

 - ~-2^{31} <= x <= 2^{31} - 1~

*Follow up:* Could you solve it without converting the integer to a string?

** TODO Approach
Write your approach here.

** TODO Python
#+begin_src python
class Solution:
    def isPalindrome(self, x: int) -> bool:
#+end_src

** TODO C++
#+begin_src cpp
class Solution {
public:
    bool isPalindrome(int x) {
        
    }
};
#+end_src