cpp-flashcards/org/study_deck_02/dsa/bit-manipulation/0260-single-number-iii.org

#+PROPERTY: STUDY_DECK_02
* TODO 0260. Single Number III :medium:
:PROPERTIES:
:NEETCODE: [[file:../../roadmap.org::*0260. Single Number III][0260. Single Number III]]
:END:

Given an integer array ~nums~, in which exactly two elements appear only once and all the other elements appear exactly twice. Find the two elements that appear only once. You can return the answer in *any order*.

You must write an algorithm that runs in linear runtime complexity and uses only constant extra space.

*Example 1:*


#+begin_src
Input: nums = [1,2,1,3,2,5]
Output: [3,5]
Explanation:  [5, 3] is also a valid answer.
#+end_src


*Example 2:*


#+begin_src
Input: nums = [-1,0]
Output: [-1,0]
#+end_src


*Example 3:*


#+begin_src
Input: nums = [0,1]
Output: [1,0]
#+end_src


*Constraints:*

 - ~2 <= nums.length <= 3 * 10^{4}~

 - ~-2^{31} <= nums[i] <= 2^{31} - 1~

 - Each integer in ~nums~ will appear twice, only two integers will appear once.

** TODO Approach
Write your approach here.

** TODO Python
#+begin_src python
class Solution:
    def singleNumber(self, nums: List[int]) -> List[int]:
#+end_src

** TODO C++
#+begin_src cpp
class Solution {
public:
    vector<int> singleNumber(vector<int>& nums) {
        
    }
};
#+end_src