cpp-flashcards/org/study_deck_02/dsa/trees/0100-same-tree.org

#+ANKI_DECK: study_deck_02
* TODO 0100. Same Tree :easy:
:PROPERTIES:
:NEETCODE: [[file:../../roadmap.org::*0100. Same Tree][0100. Same Tree]]
:END:

Given the roots of two binary trees ~p~ and ~q~, write a function to check if they are the same or not.

Two binary trees are considered the same if they are structurally identical, and the nodes have the same value.

*Example 1:*


#+begin_src
Input: p = [1,2,3], q = [1,2,3]
Output: true
#+end_src


*Example 2:*


#+begin_src
Input: p = [1,2], q = [1,null,2]
Output: false
#+end_src


*Example 3:*


#+begin_src
Input: p = [1,2,1], q = [1,1,2]
Output: false
#+end_src


*Constraints:*

 - The number of nodes in both trees is in the range ~[0, 100]~.

 - ~-10^{4} <= Node.val <= 10^{4}~

** TODO Approach
Write your approach here.

** TODO Python
#+begin_src python
# Definition for a binary tree node.
# class TreeNode:
#     def __init__(self, val=0, left=None, right=None):
#         self.val = val
#         self.left = left
#         self.right = right
class Solution:
    def isSameTree(self, p: Optional[TreeNode], q: Optional[TreeNode]) -> bool:
#+end_src

** TODO C++
#+begin_src cpp
/**
 * Definition for a binary tree node.
 * struct TreeNode {
 *     int val;
 *     TreeNode *left;
 *     TreeNode *right;
 *     TreeNode() : val(0), left(nullptr), right(nullptr) {}
 *     TreeNode(int x) : val(x), left(nullptr), right(nullptr) {}
 *     TreeNode(int x, TreeNode *left, TreeNode *right) : val(x), left(left), right(right) {}
 * };
 */
class Solution {
public:
    bool isSameTree(TreeNode* p, TreeNode* q) {
        
    }
};
#+end_src