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2026-06-01 18:12:40 +08:00
#+ANKI_DECK: study_deck_02
* TODO 2326. Spiral Matrix IV :medium:
:PROPERTIES:
:NEETCODE: [[file:../../roadmap.org::*2326. Spiral Matrix IV][2326. Spiral Matrix IV]]
:END:
You are given two integers ~m~ and ~n~, which represent the dimensions of a matrix.
You are also given the ~head~ of a linked list of integers.
Generate an ~m x n~ matrix that contains the integers in the linked list presented in *spiral* order *(clockwise)*, starting from the *top-left* of the matrix. If there are remaining empty spaces, fill them with ~-1~.
Return /the generated matrix/.
*Example 1:*
#+begin_src
Input: m = 3, n = 5, head = [3,0,2,6,8,1,7,9,4,2,5,5,0]
Output: [[3,0,2,6,8],[5,0,-1,-1,1],[5,2,4,9,7]]
Explanation: The diagram above shows how the values are printed in the matrix.
Note that the remaining spaces in the matrix are filled with -1.
#+end_src
*Example 2:*
#+begin_src
Input: m = 1, n = 4, head = [0,1,2]
Output: [[0,1,2,-1]]
Explanation: The diagram above shows how the values are printed from left to right in the matrix.
The last space in the matrix is set to -1.
#+end_src
*Constraints:*
- ~1 <= m, n <= 10^{5}~
- ~1 <= m * n <= 10^{5}~
- The number of nodes in the list is in the range ~[1, m * n]~.
- ~0 <= Node.val <= 1000~
** TODO Approach
Write your approach here.
** TODO Python
#+begin_src python
# Definition for singly-linked list.
# class ListNode:
# def __init__(self, val=0, next=None):
# self.val = val
# self.next = next
class Solution:
def spiralMatrix(self, m: int, n: int, head: Optional[ListNode]) -> List[List[int]]:
#+end_src
** TODO C++
#+begin_src cpp
/**
* Definition for singly-linked list.
* struct ListNode {
* int val;
* ListNode *next;
* ListNode() : val(0), next(nullptr) {}
* ListNode(int x) : val(x), next(nullptr) {}
* ListNode(int x, ListNode *next) : val(x), next(next) {}
* };
*/
class Solution {
public:
vector<vector<int>> spiralMatrix(int m, int n, ListNode* head) {
}
};
#+end_src