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2026-06-01 18:12:40 +08:00
#+ANKI_DECK: study_deck_02
* TODO 2300. Successful Pairs of Spells and Potions :medium:
:PROPERTIES:
:NEETCODE: [[file:../../roadmap.org::*2300. Successful Pairs of Spells and Potions][2300. Successful Pairs of Spells and Potions]]
:END:
You are given two positive integer arrays ~spells~ and ~potions~, of length ~n~ and ~m~ respectively, where ~spells[i]~ represents the strength of the ~i^{th}~ spell and ~potions[j]~ represents the strength of the ~j^{th}~ potion.
You are also given an integer ~success~. A spell and potion pair is considered *successful* if the *product* of their strengths is *at least* ~success~.
Return /an integer array /~pairs~/ of length /~n~/ where /~pairs[i]~/ is the number of *potions* that will form a successful pair with the /~i^{th}~/ spell./
*Example 1:*
#+begin_src
Input: spells = [5,1,3], potions = [1,2,3,4,5], success = 7
Output: [4,0,3]
Explanation:
- 0th spell: 5 * [1,2,3,4,5] = [5,10,15,20,25]. 4 pairs are successful.
- 1st spell: 1 * [1,2,3,4,5] = [1,2,3,4,5]. 0 pairs are successful.
- 2nd spell: 3 * [1,2,3,4,5] = [3,6,9,12,15]. 3 pairs are successful.
Thus, [4,0,3] is returned.
#+end_src
*Example 2:*
#+begin_src
Input: spells = [3,1,2], potions = [8,5,8], success = 16
Output: [2,0,2]
Explanation:
- 0th spell: 3 * [8,5,8] = [24,15,24]. 2 pairs are successful.
- 1st spell: 1 * [8,5,8] = [8,5,8]. 0 pairs are successful.
- 2nd spell: 2 * [8,5,8] = [16,10,16]. 2 pairs are successful.
Thus, [2,0,2] is returned.
#+end_src
*Constraints:*
- ~n == spells.length~
- ~m == potions.length~
- ~1 <= n, m <= 10^{5}~
- ~1 <= spells[i], potions[i] <= 10^{5}~
- ~1 <= success <= 10^{10}~
** TODO Approach
Write your approach here.
** TODO Python
#+begin_src python
class Solution:
def successfulPairs(self, spells: List[int], potions: List[int], success: int) -> List[int]:
#+end_src
** TODO C++
#+begin_src cpp
class Solution {
public:
vector<int> successfulPairs(vector<int>& spells, vector<int>& potions, long long success) {
}
};
#+end_src