2026-06-01 18:12:40 +08:00
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#+ANKI_DECK: study_deck_02
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2026-06-01 17:12:10 +08:00
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* TODO 0567. Permutation In String :medium:
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2026-06-01 02:33:30 +08:00
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:PROPERTIES:
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2026-06-01 17:22:07 +08:00
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:NEETCODE: [[file:../../roadmap.org::*0567. Permutation In String][0567. Permutation In String]]
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2026-06-01 02:33:30 +08:00
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:END:
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2026-06-01 17:22:07 +08:00
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Given two strings ~s1~ and ~s2~, return ~true~ if ~s2~ contains a permutation of ~s1~, or ~false~ otherwise.
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In other words, return ~true~ if one of ~s1~'s permutations is the substring of ~s2~.
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*Example 1:*
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#+begin_src
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Input: s1 = "ab", s2 = "eidbaooo"
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Output: true
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Explanation: s2 contains one permutation of s1 ("ba").
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#+end_src
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*Example 2:*
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#+begin_src
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Input: s1 = "ab", s2 = "eidboaoo"
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Output: false
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#+end_src
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*Constraints:*
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- ~1 <= s1.length, s2.length <= 10^{4}~
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- ~s1~ and ~s2~ consist of lowercase English letters.
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2026-06-01 02:39:53 +08:00
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** TODO Approach
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Write your approach here.
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** TODO Python
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#+begin_src python
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2026-06-01 17:22:07 +08:00
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class Solution:
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def checkInclusion(self, s1: str, s2: str) -> bool:
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2026-06-01 02:39:53 +08:00
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#+end_src
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** TODO C++
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2026-06-01 02:33:30 +08:00
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#+begin_src cpp
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2026-06-01 17:22:07 +08:00
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class Solution {
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public:
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bool checkInclusion(string s1, string s2) {
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}
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};
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2026-06-01 02:33:30 +08:00
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#+end_src
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