cpp-flashcards/org/study_deck_02/dsa/greedy/0978-longest-turbulent-subarray.org

#+ANKI_DECK: study_deck_02
* TODO 0978. Longest Turbulent Subarray :medium:
:PROPERTIES:
:NEETCODE: [[file:../../roadmap.org::*0978. Longest Turbulent Subarray][0978. Longest Turbulent Subarray]]
:END:

Given an integer array ~arr~, return /the length of a maximum size turbulent subarray of/ ~arr~.

A subarray is *turbulent* if the comparison sign flips between each adjacent pair of elements in the subarray.

More formally, a subarray ~[arr[i], arr[i + 1], ..., arr[j]]~ of ~arr~ is said to be turbulent if and only if:

 - For ~i <= k < j~:

 - ~arr[k] > arr[k + 1]~ when ~k~ is odd, and

 - ~arr[k] < arr[k + 1]~ when ~k~ is even.

 - Or, for ~i <= k < j~:
 
 - ~arr[k] > arr[k + 1]~ when ~k~ is even, and

 - ~arr[k] < arr[k + 1]~ when ~k~ is odd.

*Example 1:*


#+begin_src
Input: arr = [9,4,2,10,7,8,8,1,9]
Output: 5
Explanation: arr[1] > arr[2] < arr[3] > arr[4] < arr[5]
#+end_src


*Example 2:*


#+begin_src
Input: arr = [4,8,12,16]
Output: 2
#+end_src


*Example 3:*


#+begin_src
Input: arr = [100]
Output: 1
#+end_src


*Constraints:*

 - ~1 <= arr.length <= 4 * 10^{4}~

 - ~0 <= arr[i] <= 10^{9}~

** TODO Approach
Write your approach here.

** TODO Python
#+begin_src python
class Solution:
    def maxTurbulenceSize(self, arr: List[int]) -> int:
#+end_src

** TODO C++
#+begin_src cpp
class Solution {
public:
    int maxTurbulenceSize(vector<int>& arr) {
        
    }
};
#+end_src