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2026-06-01 18:12:40 +08:00
#+ANKI_DECK: study_deck_02
* TODO 0260. Single Number III :medium:
:PROPERTIES:
:NEETCODE: [[file:../../roadmap.org::*0260. Single Number III][0260. Single Number III]]
:END:
Given an integer array ~nums~, in which exactly two elements appear only once and all the other elements appear exactly twice. Find the two elements that appear only once. You can return the answer in *any order*.
You must write an algorithm that runs in linear runtime complexity and uses only constant extra space.
*Example 1:*
#+begin_src
Input: nums = [1,2,1,3,2,5]
Output: [3,5]
Explanation: [5, 3] is also a valid answer.
#+end_src
*Example 2:*
#+begin_src
Input: nums = [-1,0]
Output: [-1,0]
#+end_src
*Example 3:*
#+begin_src
Input: nums = [0,1]
Output: [1,0]
#+end_src
*Constraints:*
- ~2 <= nums.length <= 3 * 10^{4}~
- ~-2^{31} <= nums[i] <= 2^{31} - 1~
- Each integer in ~nums~ will appear twice, only two integers will appear once.
** TODO Approach
Write your approach here.
** TODO Python
#+begin_src python
class Solution:
def singleNumber(self, nums: List[int]) -> List[int]:
#+end_src
** TODO C++
#+begin_src cpp
class Solution {
public:
vector<int> singleNumber(vector<int>& nums) {
}
};
#+end_src