2026-06-01 18:12:40 +08:00
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#+ANKI_DECK: study_deck_02
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2026-06-01 17:12:10 +08:00
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* TODO 1408. String Matching in an Array :easy:
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2026-06-01 02:33:30 +08:00
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:PROPERTIES:
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2026-06-01 17:22:07 +08:00
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:NEETCODE: [[file:../../roadmap.org::*1408. String Matching in an Array][1408. String Matching in an Array]]
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2026-06-01 02:33:30 +08:00
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:END:
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2026-06-01 17:22:07 +08:00
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Given an array of string ~words~, return all strings in/ /~words~/ /that are a substring of another word. You can return the answer in *any order*.
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*Example 1:*
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#+begin_src
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Input: words = ["mass","as","hero","superhero"]
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Output: ["as","hero"]
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Explanation: "as" is substring of "mass" and "hero" is substring of "superhero".
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["hero","as"] is also a valid answer.
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#+end_src
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*Example 2:*
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#+begin_src
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Input: words = ["leetcode","et","code"]
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Output: ["et","code"]
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Explanation: "et", "code" are substring of "leetcode".
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#+end_src
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*Example 3:*
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#+begin_src
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Input: words = ["blue","green","bu"]
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Output: []
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Explanation: No string of words is substring of another string.
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#+end_src
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*Constraints:*
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- ~1 <= words.length <= 100~
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- ~1 <= words[i].length <= 30~
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- ~words[i]~ contains only lowercase English letters.
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- All the strings of ~words~ are *unique*.
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2026-06-01 02:39:53 +08:00
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** TODO Approach
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Write your approach here.
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** TODO Python
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#+begin_src python
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2026-06-01 17:22:07 +08:00
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class Solution:
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def stringMatching(self, words: List[str]) -> List[str]:
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2026-06-01 02:39:53 +08:00
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#+end_src
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** TODO C++
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2026-06-01 02:33:30 +08:00
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#+begin_src cpp
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2026-06-01 17:22:07 +08:00
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class Solution {
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public:
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vector<string> stringMatching(vector<string>& words) {
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}
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};
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2026-06-01 02:33:30 +08:00
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#+end_src
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