cpp-flashcards/org/study_deck_02/dsa/greedy/0053-maximum-subarray.org

#+PROPERTY: STUDY_DECK_02
* TODO 0053. Maximum Subarray :medium:
:PROPERTIES:
:NEETCODE: [[file:../../roadmap.org::*0053. Maximum Subarray][0053. Maximum Subarray]]
:END:

Given an integer array ~nums~, find the subarray with the largest sum, and return /its sum/.

*Example 1:*


#+begin_src
Input: nums = [-2,1,-3,4,-1,2,1,-5,4]
Output: 6
Explanation: The subarray [4,-1,2,1] has the largest sum 6.
#+end_src


*Example 2:*


#+begin_src
Input: nums = [1]
Output: 1
Explanation: The subarray [1] has the largest sum 1.
#+end_src


*Example 3:*


#+begin_src
Input: nums = [5,4,-1,7,8]
Output: 23
Explanation: The subarray [5,4,-1,7,8] has the largest sum 23.
#+end_src


*Constraints:*

 - ~1 <= nums.length <= 10^{5}~

 - ~-10^{4} <= nums[i] <= 10^{4}~

*Follow up:* If you have figured out the ~O(n)~ solution, try coding another solution using the *divide and conquer* approach, which is more subtle.

** TODO Approach
Write your approach here.

** TODO Python
#+begin_src python
class Solution:
    def maxSubArray(self, nums: List[int]) -> int:
#+end_src

** TODO C++
#+begin_src cpp
class Solution {
public:
    int maxSubArray(vector<int>& nums) {
        
    }
};
#+end_src