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#+PROPERTY: STUDY_DECK_02
* TODO 0347. Top K Frequent Elements :medium:
:PROPERTIES:
:NEETCODE: [[file:../../roadmap.org::*0347. Top K Frequent Elements][0347. Top K Frequent Elements]]
:END:
Given an integer array ~nums~ and an integer ~k~, return /the/ ~k~ /most frequent elements/. You may return the answer in *any order*.
*Example 1:*
*Input:* nums = [1,1,1,2,2,3], k = 2
*Output:* [1,2]
*Example 2:*
*Input:* nums = [1], k = 1
*Output:* [1]
*Example 3:*
*Input:* nums = [1,2,1,2,1,2,3,1,3,2], k = 2
*Output:* [1,2]
*Constraints:*
- ~1 <= nums.length <= 10^{5}~
- ~-10^{4} <= nums[i] <= 10^{4}~
- ~k~ is in the range ~[1, the number of unique elements in the array]~.
- It is *guaranteed* that the answer is *unique*.
*Follow up:* Your algorithm's time complexity must be better than ~O(n log n)~, where n is the array's size.
** TODO Approach
Write your approach here.
** TODO Python
#+begin_src python
class Solution:
def topKFrequent(self, nums: List[int], k: int) -> List[int]:
#+end_src
** TODO C++
#+begin_src cpp
class Solution {
public:
vector<int> topKFrequent(vector<int>& nums, int k) {
}
};
#+end_src