2026-06-01 18:12:40 +08:00
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#+ANKI_DECK: study_deck_02
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2026-06-01 17:12:10 +08:00
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* TODO 1448. Count Good Nodes In Binary Tree :medium:
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2026-06-01 02:33:30 +08:00
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:PROPERTIES:
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2026-06-01 17:22:07 +08:00
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:NEETCODE: [[file:../../roadmap.org::*1448. Count Good Nodes In Binary Tree][1448. Count Good Nodes In Binary Tree]]
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2026-06-01 02:33:30 +08:00
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:END:
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2026-06-01 17:22:07 +08:00
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Given a binary tree ~root~, a node /X/ in the tree is named *good* if in the path from root to /X/ there are no nodes with a value /greater than/ X.
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Return the number of *good* nodes in the binary tree.
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*Example 1:*
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**
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#+begin_src
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Input: root = [3,1,4,3,null,1,5]
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Output: 4
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Explanation: Nodes in blue are good.
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Root Node (3) is always a good node.
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Node 4 -> (3,4) is the maximum value in the path starting from the root.
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Node 5 -> (3,4,5) is the maximum value in the path
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Node 3 -> (3,1,3) is the maximum value in the path.
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#+end_src
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*Example 2:*
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**
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#+begin_src
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Input: root = [3,3,null,4,2]
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Output: 3
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Explanation: Node 2 -> (3, 3, 2) is not good, because "3" is higher than it.
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#+end_src
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*Example 3:*
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#+begin_src
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Input: root = [1]
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Output: 1
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Explanation: Root is considered as good.
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#+end_src
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*Constraints:*
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- The number of nodes in the binary tree is in the range ~[1, 10^5]~.
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- Each node's value is between ~[-10^4, 10^4]~.
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2026-06-01 02:39:53 +08:00
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** TODO Approach
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Write your approach here.
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** TODO Python
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2026-06-05 22:32:49 +08:00
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#+begin_src python :lc-problem 1448 :lc-lang python3
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2026-06-01 17:22:07 +08:00
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# Definition for a binary tree node.
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# class TreeNode:
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# def __init__(self, val=0, left=None, right=None):
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# self.val = val
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# self.left = left
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# self.right = right
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class Solution:
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def goodNodes(self, root: TreeNode) -> int:
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2026-06-01 02:39:53 +08:00
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#+end_src
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** TODO C++
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2026-06-05 22:32:49 +08:00
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#+begin_src cpp :lc-problem 1448
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2026-06-01 17:22:07 +08:00
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/**
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* Definition for a binary tree node.
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* struct TreeNode {
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* int val;
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* TreeNode *left;
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* TreeNode *right;
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* TreeNode() : val(0), left(nullptr), right(nullptr) {}
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* TreeNode(int x) : val(x), left(nullptr), right(nullptr) {}
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* TreeNode(int x, TreeNode *left, TreeNode *right) : val(x), left(left), right(right) {}
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* };
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*/
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class Solution {
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public:
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int goodNodes(TreeNode* root) {
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}
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};
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2026-06-01 02:33:30 +08:00
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#+end_src
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